Tables of percentage points of noncentral x

Abstract

The authors are grateful to Mr Harold W. Peers for pointing out a mistake on p. 261 due to having taken the wrong root of the quadratic for c . The correct solution involves the following changes: (a) Equations (14) should be modified to read: c = ( 2 μ ′ 1 ) - 1 { μ 2 - ( μ 2 2 - 1 2 μ ′ 1 μ 3 ) } , v = 2 μ ′ 1 c - 1 - 1 2 μ 2 c - 2 , λ = 1 2 μ 2 c - 2 - μ ′ 1 c - 1 (b) The following line should read: ‘Note that λ cannot be negative if…’ (c) Equation (15) should read: 2 3 μ ′ 1 μ 3 ≥ μ 2 2 ≥ 1 2 μ ′ 1 μ 3 . (d) In the following line, replace ‘at least ½√β 1 ’ by ‘between ⅔√β 1 and ½√β 1 ’.